Golang を使用して RabbitMQ と効率的に通信するにはどうすればよいですか?

go get github.com/streadway/amqp

import (
    "log"
    "github.com/streadway/amqp"
)

func main() {
    conn, err := amqp.Dial("amqp://guest:guest@localhost:5672/")
    if err != nil {
        log.Fatalf("Failed to connect to RabbitMQ: %v", err)
    }
    defer conn.Close()

    ch, err := conn.Channel()
    if err != nil {
        log.Fatalf("Failed to open a channel: %v", err)
    }
    defer ch.Close()
}

q, err := ch.QueueDeclare(
    "my_queue", // 队列名称
    false,  // 是否持久化
    false, // 是否自动删除
    false, // 是否独占连接
    false, // 是否等待连接上的消费者
    nil, // 额外的参数
)
if err != nil {
    log.Fatalf("Failed to declare a queue: %v", err)
}

err = ch.Publish(
    "",    // exchange
    q.Name, // routing key
    false,  // mandatory
    false, // immediate
    amqp.Publishing{
        ContentType: "text/plain",
        Body:        []byte("Hello RabbitMQ!"),
    })
if err != nil {
    log.Fatalf("Failed to publish a message: %v", err)
}

msgs, err := ch.Consume(
    q.Name, // queue
    "",   // consumer
    true, // auto-ack
    false, // exclusive
    false, // no-local
    false, // no-wait
    nil, // args
)
if err != nil {
    log.Fatalf("Failed to consume a message: %v", err)
}

for msg := range msgs {
    log.Printf("Received a message: %s", msg.Body)
}

defer ch.Close()
defer conn.Close()