C 言語を使用して 2 つの浮動小数点または倍精度数値の係数を計算します。

remainder(x, y) = x – rquote * y

#include <stdio.h>
#include <math.h>
main() {
   double x = 14.5, y = 4.1;
   double res = remainder(x, y);
   printf("Remainder of %lf/%lf is: %lf</p><p>",x,y, res);
   x = -34.50;
   y = 4.0;
   res = remainder(x, y);
   printf("Remainder of %lf/%lf is: %lf</p><p>",x,y, res);
   x = 65.23;
   y = 0;
   res = remainder(x, y);
   printf("Remainder of %lf/%lf is: %lf</p><p>",x,y, res);
}

Remainder of 14.500000/4.100000 is: -1.900000
Remainder of -34.500000/4.000000 is: 1.500000
Remainder of 65.230000/0.000000 is: -1.#IND00