LIKE 句を使用して MySQL テーブル内のデータを照合する PHP スクリプトを作成するにはどうすればよいですか?

<?php
   $dbhost = &#39;localhost:3036&#39;;
   $dbuser = &#39;root&#39;;
   $dbpass = &#39;rootpassword&#39;;
   $conn = mysql_connect($dbhost, $dbuser, $dbpass);
   
   if(! $conn ) {
      die(&#39;Could not connect: &#39; . mysql_error());
   }
   
   $sql = &#39;SELECT tutorial_id, tutorial_title,
      tutorial_author, submission_date
      FROM tutorials_tbl
      WHERE tutorial_author LIKE "%jay%"&#39;;
     
   mysql_select_db(&#39;TUTORIALS&#39;);
   $retval = mysql_query( $sql, $conn );

   if(! $retval ) {
      die(&#39;Could not get data: &#39; . mysql_error());
   }
   
   while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
      echo "Tutorial ID :{$row[&#39;tutorial_id&#39;]} <br> ".
         "Title: {$row[&#39;tutorial_title&#39;]} <br> ".
         "Author: {$row[&#39;tutorial_author&#39;]} <br> ".
         "Submission Date : {$row[&#39;submission_date&#39;]} <br> ".
         "--------------------------------<br>";
   }
   echo "Fetched data successfully</p><p>";
   mysql_close($conn);
?>