C++ で書かれており、すべての要素が X より大きいセグメントの数を見つけます。

Input : arr[ ] = { 9, 6, 7, 11, 5, 7, 8, 10, 3}, X = 7 Output : 3 Explanation : { 9 }, { 11 } and { 8, 10 } are the segments greater than 7 Input : arr[ ] = { 9, 6, 12, 2, 11, 14, 8, 14 }, X = 8 Output : 4 Explanation : { 9 }, { 12 }, { 11, 14 } and { 14 } are the segments greater than 8

#include  using namespace std; int main (){ int a[] = { 9, 6, 12, 2, 11, 14, 8, 14 }; int n = sizeof (a) / sizeof (a[0]); int X = 8; int state = 0; int count = 0; // traverse the array for (int i = 0; i < n; i++){ // checking whether element is greater than X if (a[i] > X){ state = 1; } else{ // if flag is true if (state) count += 1; state = 0; } } // checking for the last segment if (state) count += 1; cout << "Number of segments where all elements are greater than X: " << count; return 0; }

Number of segments where all elements are greater than X: 4