JAVAでJSON配列を解析して走査するにはどうすればよいですか? JSON 配列処理スキルをマスターします。

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-core</artifactId>
    <version>2.12.3</version>
</dependency>
<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.12.3</version>
</dependency>

[
    {
        "name": "Alice",
        "age": 25
    },
    {
        "name": "Bob",
        "age": 28
    },
    {
        "name": "Charlie",
        "age": 30
    }
]

public class Person {
    private String name;
    private int age;

    // 省略getter和setter方法
}

import com.fasterxml.jackson.databind.ObjectMapper;

import java.io.IOException;

public class JsonArrayParsingExample {
    public static void main(String[] args) {
        String json = "[{"name":"Alice","age":25},{"name":"Bob","age":28},{"name":"Charlie","age":30}]";

        ObjectMapper objectMapper = new ObjectMapper();
        try {
            Person[] persons = objectMapper.readValue(json, Person[].class);

            // 遍历数组
            for (Person person : persons) {
                System.out.println("Name: " + person.getName() + ", Age: " + person.getAge());
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

Name: Alice, Age: 25
Name: Bob, Age: 28
Name: Charlie, Age: 30

import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;

import java.io.IOException;

public class JsonArrayParsingExample {
    public static void main(String[] args) {
        String json = "[{"name":"Alice","age":25},{"title":"Software Engineer","salary":5000}]";

        ObjectMapper objectMapper = new ObjectMapper();
        try {
            JsonNode[] nodes = objectMapper.readValue(json, JsonNode[].class);

            // 遍历数组
            for (JsonNode node : nodes) {
                // 判断节点类型
                if (node.has("name")) {
                    String name = node.get("name").asText();
                    int age = node.get("age").asInt();
                    System.out.println("Name: " + name + ", Age: " + age);
                } else if (node.has("title")) {
                    String title = node.get("title").asText();
                    int salary = node.get("salary").asInt();
                    System.out.println("Title: " + title + ", Salary: " + salary);
                }
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

Name: Alice, Age: 25
Title: Software Engineer, Salary: 5000