他の文字の頻度の合計よりも頻度が高い文字と連結される文字列の数を計算します。

Let us take the input array 
arr[]: {“xyz", “yyyyx", “q”}

Output obtained is: 3

Let us take the input array 
arr[]: {“mnoml", “lmll", “nln”, "mnlmn"}

Output obtained is : 2

#include <stdio.h>
#include <stdlib.h>
//input strings to be non-empty and not more //than 100 characters
#define MAX_STR_LEN 100

// Function to determine the frequencies of all the characters and reducing the sum of other frequencies in the strings
int* frequency(char** a, int len, char c){

   // We use array to store the frequency
   int* v = (int*)calloc(len, sizeof(int));
   if(v == NULL) {
      printf("Error: Memory allocation failed");
      exit(1);
   }
   
   // Iterating the array a of strings
   for (int i = 0; i < len; i++) {
      char* str = a[i];
      
      // defining an integer variable for storing //the frequencies
      int net_fre = 0;
      
      // Iterating through the string str
      for (int j = 0; str[j] != '\0'; j++) {
      
         // If str[j] is equal to the current character increment the net_fre by 1
         if (str[j] == c)
            net_fre++;
            
         // otherwise decrement net_fre by 1
         else
            net_fre--;
      }
      
      // After iterating the string store this frequency in the array v
      v[i] = net_fre;
   }
   
   //return the array v
   return v;
}

// Function to determine the count of the longest or the lengthiest string that could be obtained from the given array of strings
int longestConcatenatedString(char** a, int len){

   // An integer variable to store the maximum count Also it is set to zero
   int mxm = 0;
   
   // Iterating through all of the alphabets
   for (char c = 'a'; c <= 'z'; c++) {
   
      // Array to store the net_frequency of the character c after reducing the sum of every other frequencies in all of the strings
      int* v = frequency(a, len, c);
      
      // Array is stored in the order of descendants
      for (int i = 0; i < len - 1; i++) {
         for (int j = i + 1; j < len; j++) {
            if (v[i] < v[j]) {
               int temp = v[i];
               v[i] = v[j];
               v[j] = temp;
               char* temp_str = a[i];
               a[i] = a[j];
               a[j] = temp_str;
            }
         }
      }
      
      // Variable res is defined to store the //result
      int res = 0;
      int sum = 0;
      for (int i = 0; i < len; i++) {
         sum += v[i];
         
         // If sum is greater than 0 then increment res by 1
         if (sum > 0) {
            res++;
         }
      }
      
      // Keeping the track of the maximum one
      mxm = mxm > res ? mxm : res;
      free(v);
   }
   
   // Returning the maximum value obtained
   return mxm;
}
int main(){
   char* a[] = { "mnoml", "lmll", "nln", "mnlmn" };
   printf("Count of strings to be concatenated with a character having frequency greater than sum of others: ");
   int len = sizeof(a) / sizeof(a[0]);
   printf("%d", longestConcatenatedString(a, len));
   return 0;
}

Count of strings to be concatenated with a character having frequency greater than sum of others: 2