Java では、例外を再スローするとはどういう意味ですか?

try {
   int result = (arr[a])/(arr[b]);
   System.out.println("Result of "+arr[a]+"/"+arr[b]+": "+result);
}
catch(ArithmeticException e) {
   throw e;
}

try {
   int result = (arr[a])/(arr[b]);
   System.out.println("Result of "+arr[a]+"/"+arr[b]+": "+result);
}
catch(ArrayIndexOutOfBoundsException e) {
   throw new IndexOutOfBoundsException();
}

import java.util.Arrays;
import java.util.Scanner;
public class RethrowExample {
   public void demoMethod() {
      Scanner sc = new Scanner(System.in);
      int[] arr = {10, 20, 30, 2, 0, 8};
      System.out.println("Array: "+Arrays.toString(arr));
      System.out.println("Choose numerator and denominator(not 0) from this array (enter positions 0 to 5)");
      int a = sc.nextInt();
      int b = sc.nextInt();
      try {
         int result = (arr[a])/(arr[b]);
         System.out.println("Result of "+arr[a]+"/"+arr[b]+": "+result);
      }
      catch(ArrayIndexOutOfBoundsException e) {
         throw new IndexOutOfBoundsException();
      }
      catch(ArithmeticException e) {
         throw e;
      }
   }
   public static void main(String [] args) {
      new RethrowExample().demoMethod();
   }
}

Array: [10, 20, 30, 2, 0, 8]
Choose numerator and denominator(not 0) from this array (enter positions 0 to 5)
0
4
Exception in thread "main" java.lang.ArithmeticException: / by zero
   at myPackage.RethrowExample.demoMethod(RethrowExample.java:16)
   at myPackage.RethrowExample.main(RethrowExample.java:25)

Array: [10, 20, 30, 2, 0, 8]
Choose numerator and denominator(not 0) from this array (enter positions 0 to 5)
124
5
Exception in thread "main" java.lang.IndexOutOfBoundsException
   at myPackage.RethrowExample.demoMethod(RethrowExample.java:17)
   at myPackage.RethrowExample.main(RethrowExample.java:23)