Java ネットワーク接続リダイレクト例外 (RedirectException) を解決する方法

import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.URL;

public class RedirectHandler {

    public void handleRedirect(String urlString) throws IOException {
        URL url = new URL(urlString);
        HttpURLConnection connection = (HttpURLConnection) url.openConnection();
        connection.setInstanceFollowRedirects(false); // 禁止自动处理重定向
        int responseCode = connection.getResponseCode();

        if (responseCode == HttpURLConnection.HTTP_MOVED_PERM || responseCode == HttpURLConnection.HTTP_MOVED_TEMP ||
                responseCode == HttpURLConnection.HTTP_SEE_OTHER) {
            String newUrl = connection.getHeaderField("Location"); // 获取新的重定向URL
            connection = (HttpURLConnection) new URL(newUrl).openConnection();
        }

        // 处理重定向后的请求
        // ...
    }

    public static void main(String[] args) {
        RedirectHandler handler = new RedirectHandler();
        try {
            handler.handleRedirect("http://example.com");
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.utils.URIBuilder;
import org.apache.http.impl.client.HttpClientBuilder;

import java.io.IOException;
import java.net.URI;
import java.net.URISyntaxException;

public class RedirectHandler {

    public void handleRedirect(String urlString) throws IOException, URISyntaxException {
        URI uri = new URIBuilder(urlString).build();
        HttpClient httpClient = HttpClientBuilder.create().build();
        HttpGet httpGet = new HttpGet(uri);

        // 自动处理重定向
        httpClient.execute(httpGet);

        // 处理重定向后的请求
        // ...
    }

    public static void main(String[] args) {
        RedirectHandler handler = new RedirectHandler();
        try {
            handler.handleRedirect("http://example.com");
        } catch (IOException | URISyntaxException e) {
            e.printStackTrace();
        }
    }
}