Java で頻繁に聞かれる基本的な面接の質問—(9)

student(sno,sname,sage,ssex)学生表 course(cno,cname,tno) 课程表 sc(sno,cno,score) 成绩表 teacher(tno,tname) 教师表

select a.sno from (select sno,score from sc where cno=1) a, (select sno,score from sc where cno=2) b where a.score>b.score and a.sno=b.sno

select a.sno as "学号", avg(a.score) as "平均成绩" from (select sno,score from sc) a group by sno having avg(a.score)>60

select a.sno as 学号, b.sname as 姓名, count(a.cno) as 选课数, sum(a.score) as 总成绩 from sc a, student b where a.sno = b.sno group by a.sno, b.sname

selectstudent.sno as 学号, student.sname as 姓名, count(sc.cno) as 选课数, sum(score) as 总成绩 from student left Outer join sc on student.sno = sc.sno group by student.sno, sname

selectcount(distinct(tname)) from teacher where tname like '张%‘

select tname as "姓名", count(distinct(tname)) as "人数" from teacher where tname like'张%' group by tname

select student.sno,student.sname from student where sno not in (select distinct(sc.sno) from sc,course,teacher where sc.cno=course.cno and teacher.tno=course.tno and teacher.tname='张三')

select sno, sname from student where sno in (select sno from sc where sc.cno = 1) and sno in (select sno from sc where sc.cno = 2)

selectc.sno, c.sname from (select sno from sc where sc.cno = 1) a, (select sno from sc where sc.cno = 2) b, student c where a.sno = b.sno and a.sno = c.sno

select student.sno,student.sname from student,sc where student.sno=sc.sno and sc.cno=1 and exists( select * from sc as sc_2 where sc_2.sno=sc.sno and sc_2.cno=2)

select a.sno, a.sname from student a, sc b where a.sno = b.sno and b.cno in (select c.cno from course c, teacher d where c.tno = d.tno and d.tname = '李四')

select a.sno, a.sname from student a, sc b, (select c.cno from course c, teacher d where c.tno = d.tno and d.tname = '李四') e where a.sno = b.sno and b.cno = e.cno

select a.sno, a.sname from student a, (select sno, score from sc where cno = 1) b, (select sno, score from sc where cno = 2) c where b.score > c.score and b.sno = c.sno and a.sno = b.sno

select sno,sname from student where sno not in (select distinct sno from sc where score > 60)

select distinct a.sno, a.sname from student a, sc b where a.sno <> 1 and a.sno=b.sno and b.cno in (select cno from sc where sno = 1)

select s.sno,s.sname from student s, (select sc.sno from sc where sc.cno in (select sc1.cno from sc sc1 where sc1.sno=1)and sc.sno<>1 group by sc.sno)r1 where r1.sno=s.sno