Pythonでランダムなパスワードを生成するにはどうすればよいですか?

import random def random_password(): list1 = [] #把字母加入序列中 for i in range(65,90): list1.append(chr(i)) for i in range(97,122): list1.append(chr(i)) list2 = [1,2,3,4,5,6,7,8,9] list = list1 +list2 n = 0 while n < 10: password = [] n = n + 1 m = 0 password = password + random.sample(list, 8) #把列表转化为字符串 password_middle = [str(i) for i in password] password_end = ''.join(password_middle) print("第{}个随机生成的密码是：{}".format(n,password_end)) random_password() #random.sample(seq, k)实现从序列或集合seq中随机选取k个独立的的元素 #random.randint(a, b) #A-Z:65-90;a-z：97-122;ASCII码48～57为0到9十个阿拉伯数字

import random random.seed(0x1010) #设置随机种子数 #设置种子选择空间 s = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890!@#$%^&*" ls = [] #存取密码的列表 FirstPsw = "" #存取第一个密码的字符 while len(ls)<20: #十个随机密码 pwd = "" for i in range(10): pwd += s[random.randint(0,len(s)-1)] if pwd[0] in FirstPsw: continue else: ls.append(pwd) FirstPsw +=pwd[0] fo = open("随机密码.txt","w",encoding ="utf-8") fo.write("\n".join(ls)) fo.close()

#-*-coding:utf_8-*- import random,string #调用random、string模块 src_digits = string.digits #string_数字 src_uppercase = string.ascii_uppercase #string_大写字母 src_lowercase = string.ascii_lowercase #string_小写字母 count = int(input("请输入生成密码个数：")) for i in range(count): #随机生成数字、大写字母、小写字母的组成个数（可根据实际需要进行更改） digits_num = random.randint(1,6) uppercase_num = random.randint(1,8-digits_num-1) lowercase_num = 8 - (digits_num + uppercase_num) #生成字符串 password = random.sample(src_digits,digits_num) + random.sample(src_uppercase,uppercase_num) + random.sample(src_lowercase,lowercase_num) #打乱字符串 random.shuffle(password) #列表转字符串 new_password = ''.join(password) print(new_password)