PHP int は、大きなオーバーフロー整数の加算および減算関数です。より良い方法がある場合は、ぜひ議論してください。

<br />
一代码太多；<br />
二只有加减运算，乘除取余都没有；<br />

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mysql> SELECT 11234123413241341234123412341234+1;<br />
+------------------------------------+<br />
| 11234123413241341234123412341234+1 |<br />
+------------------------------------+<br />
|   11234123413241341234123412341235 |<br />
+------------------------------------+<br />
1 row in set (0.00 sec)<br />
<br />
<br />
mysql> SELECT 11234123413241341234123412341234*12341234123;<br />
+----------------------------------------------+<br />
| 11234123413241341234123412341234*12341234123 |<br />
+----------------------------------------------+<br />
|   138642947209487270472850788378836360727782 |<br />
+----------------------------------------------+<br />
1 row in set (0.00 sec)<br />
<br />
<br />

<br>
/* big int 演算 [by fuzb 20130826] */<br>
関数 bigintO($num1,$op,$num2)<br>
{<br>
$arr = array();<br>
$endop = '';<br>
$num1o = $num1;<br>
$num2o = $num2;<br>
If($num1 
{<br>
$c1 = -1;<br>
$num1 = preg_replace('/^(-)/','',$num1);<br>
<br>
} else {<br>
$c1 = 1;<br>
}<br>
<br>
If($num2 
{<br>
$c2 = -1;<br>
$num2 = preg_replace('/^(-)/','',$num2);<br>
} else {<br>
$c2 = 1;<br>
}<br>
<br>
$len1 = strlen($num1);<br>
$len2 = strlen($num2);<br>
$len = max(strlen($num1),strlen($num2));<br>
If($len1 
If($len2 
<br>
<br>
If($op == ' ')<br>
{<br>
If($c1 == $c2)<br>
{ <div class="clear"></div>