PostgreSQL クエリで連続した行番号を生成するにはどうすればよいですか?

select row_number() over (order by <field> nulls last) as rownum, *
from <table_name>
order by <field>;

select row_number() over (order by id nulls last) as rownum, *
from foo_tbl
order by id;

select row_number() over(), *  -- no fields are needed
from foo_tbl;

import sqlalchemy

# Create a test table
engine = sqlalchemy.create_engine('postgresql://postgres:my_password@localhost:5432/test_db')
metadata = sqlalchemy.MetaData()
table = sqlalchemy.Table('test_table', metadata,
    sqlalchemy.Column('id', sqlalchemy.Integer, primary_key=True),
    sqlalchemy.Column('name', sqlalchemy.String(255)),
    sqlalchemy.Column('score', sqlalchemy.Float),
)
metadata.create_all(engine)

# Insert some data into the table
insert_data = [
    {'id': 1, 'name': 'John', 'score': 90},
    {'id': 2, 'name': 'Jane', 'score': 85},
    {'id': 3, 'name': 'Bob', 'score': 95},
]
insert = table.insert().values(insert_data)
engine.execute(insert)

# Query the table with row numbers
select_query = sqlalchemy.select([
    sqlalchemy.func.row_number().over().label('rownum'),
    table.c.id,
    table.c.name,
    table.c.score,
]).order_by(table.c.id)
results = engine.execute(select_query).fetchall()

# Print the results
for result in results:
    print(f"Row {result.rownum}: {result.id}, {result.name}, {result.score}")