Java で署名付きバイトを署名なしとして正しく扱うにはどうすればよいですか?

public static int unsignedToBytes(byte a) {
    int b = a & 0xFF;
    return b;
}

int i = 200; // 0000 0000 0000 0000 0000 0000 1100 1000 (200)
byte b = (byte) i; // 1100 1000 (-56 by Java specification, 200 by convention)

/*
 * When b is cast back to int, sign extension leads to:
 * 1111 1111 1111 1111 1111 1111 1100 1000 (-56)
 *
 * However, we choose to interpret this as +200 instead.
 */
System.out.println(b); // "-56"

/*
 * To eliminate sign extension, we perform a bitwise AND with 0xFF:
 * 1111 1111 1111 1111 1111 1111 1100 1000 (the int)
 * &
 * 0000 0000 0000 0000 0000 0000 1111 1111 (0xFF)
 * =======================================
 * 0000 0000 0000 0000 0000 0000 1100 1000 (200)
 */
System.out.println(b & 0xFF); // "200"