Pandas DataFrame のカンマ区切り値を個別の行に分割するにはどうすればよいですか?

df.explode('column_name')

df.explode(['column1', 'column2'])

df = pd.DataFrame({
    'A': [[0, 1, 2], 'foo', [], [3, 4]],
    'B': 1,
    'C': [['a', 'b', 'c'], np.nan, [], ['d', 'e']]
})

df.explode('A')

     A  B          C
0    0  1  [a, b, c]
0    1  1  [a, b, c]
0    2  1  [a, b, c]
1  foo  1        NaN
2  NaN  1         []
3    3  1     [d, e]
3    4  1     [d, e]

def explode(df, lst_cols, fill_value='', preserve_index=False):
    # Ensure `lst_cols` is list-alike
    if lst_cols and not isinstance(lst_cols, (list, tuple, np.ndarray, pd.Series)):
        lst_cols = [lst_cols]

    # Calculate lengths of lists
    lens = df[lst_cols[0]].str.len()

    # Preserve original index values
    idx = np.repeat(df.index.values, lens)

    # Create an "exploded" DataFrame
    res = (pd.DataFrame({
                col:np.repeat(df[col].values, lens)
                for col in df.columns.difference(lst_cols)
            },
            index=idx)
             .assign(**{col:np.concatenate(df.loc[lens>0, col].values)
                            for col in lst_cols}))

    # Append rows with empty lists
    if (lens == 0).any():
        res = (res.append(df.loc[lens==0, df.columns.difference(lst_cols)], sort=False)
                  .fillna(fill_value))

    # Revert to original index order and reset if requested
    res = res.sort_index()
    if not preserve_index:        
        res = res.reset_index(drop=True)

    return res

df = pd.DataFrame({
    'var1': 'a,b,c d,e,f,x,y'.split(),
    'var2': [1, 2]
})

explode(df.assign(var1=df.var1.str.split(',')), 'var1')

  var1  var2
0    a     1
1    b     1
2    c     1
3    d     2
4    e     2
5    f     2
6    x     2
7    y     2