Go はクロージャでキャプチャされたループ変数をどのように処理しますか? それがなぜ重要ですか?

func main() {
    lab1() // captured closure is not what is expected

    lab2() // captured closure is not what is expected

    lab3() // captured closure behaves ok
}

func lab3() {
    m := make(map[int32]int32)
    for i := 1; i <= 10; i++ {
        m[i] = i
    }

    l := [](func() (int32, int32)){}
    for k, v := range m {
        kLocal, vLocal := k, v // (C) captures just the right values assigned to k and v
        l = append(l, func() (int32, int32) {
            return kLocal, vLocal
        })
    }

    for _, x := range l {
        k, v := x()
        fmt.Println(k, v)
    }
}

func lab2() {
    m := make(map[int32]int32)
    for i := 1; i <= 10; i++ {
        m[i] = i
    }

    l := [](func() (int32, int32)){}
    for k, v := range m {
        l = append(l, func() (int32, int32) {
            kLocal, vLocal := k, v // (B) captures just the last values assigned to k and v from the range
            return kLocal, vLocal
        })
    }

    for _, x := range l {
        k, v := x()
        fmt.Println(k, v)
    }
}

func lab1() {
    m := make(map[int32]int32)
    for i := 1; i <= 10; i++ {
        m[i] = i
    }

    l := [](func() (int32, int32)){}
    for k, v := range m {
        l = append(l, func() (int32, int32) { return k, v }) // (A) captures just the last values assigned to k and v from the range
    }

    for _, x := range l {
        k, v := x()
        fmt.Println(k, v)
    }
}