XPath を使用して Java で名前空間を含む XML をクエリする方法

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<workbook xmlns="http://schemas.openxmlformats.org/spreadsheetml/2006/main" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships">
    <sheets>
        <sheet name="Sheet1" sheetId="1" r:id="rId1"/>
    </sheets>
</workbook>

NamespaceContext namespaceContext = new NamespaceContext() {
    @Override
    public String getNamespaceURI(String prefix) {
        if (prefix.equals("main")) {
            return "http://schemas.openxmlformats.org/spreadsheetml/2006/main";
        } else if (prefix.equals("r")) {
            return "http://schemas.openxmlformats.org/officeDocument/2006/relationships";
        }
        return null;
    }
};
XPathFactory xPathFactory = XPathFactory.newInstance();
XPath xPath = xPathFactory.newXPath();
xPath.setNamespaceContext(namespaceContext);

NodeList nodes = (NodeList) xPath.evaluate("/main:workbook/main:sheets/main:sheet[1]", document, XPathConstants.NODESET);

XPathFactory xPathFactory = XPathFactory.newInstance();
XPath xPath = xPathFactory.newXPath();

NodeList nodes = (NodeList) xPath.evaluate("/*[local-name()='workbook' and namespace-uri()='http://schemas.openxmlformats.org/spreadsheetml/2006/main']" +
        "/*[local-name()='sheets' and namespace-uri()='http://schemas.openxmlformats.org/spreadsheetml/2006/main']" +
        "/*[local-name()='sheet' and namespace-uri()='http://schemas.openxmlformats.org/spreadsheetml/2006/main'][1]",
        document, XPathConstants.NODESET);