明示的な参照を行わずに C で静的メンバーの初期化を強制する方法は?

<code class="cpp">template <class D>
char register_() {
  return D::get_dummy(); // static function
}

template <class D>
struct Foo {
  static char const dummy;
};

template <class D>
char const Foo<D>::dummy = register_<D>(); // static member initialized with `register_<D>()`

struct Bar : Foo<Bar> {
  static char const get_dummy() { return 42; }
};</code>

<code class="cpp">static char const get_dummy() { (void)dummy; return 42; }</code>

<code class="cpp">template<typename T, T> struct value { };

template<typename T>
struct HasStatics {
  static int a; // we force this to be initialized
  typedef value<int&, a> value_user;
};

template<typename T>
int HasStatics<T>::a = /* whatever side-effect you want */ 0;</code>

<code class="cpp">template<typename T, T> struct var { enum { value }; };

template<typename T>
struct HasStatics {
  static int a; // we force this to be initialized
  static int b; // and this
  char user :var<int&, a>::value,
       :var<int&, b>::value;
};

template<typename T>
int HasStatics<T>::a = /* whatever side-effect you want */ 0;

template<typename T>
int HasStatics<T>::b = /* whatever side-effect you want */ 0;</code>