cURL を使用してページ コンテンツを効果的に取得するにはどうすればよいですか?

<code class="php">/**
 * Function to retrieve a web page using cURL.
 */
function get_web_page(string $url): array
{
    $user_agent = 'Mozilla/5.0 (Windows NT 6.1; rv:8.0) Gecko/20100101 Firefox/8.0';

    $options = [
        CURLOPT_CUSTOMREQUEST  => "GET",        // Set request type as GET
        CURLOPT_POST           => false,        // Set to GET
        CURLOPT_USERAGENT      => $user_agent, // Set user agent
        CURLOPT_COOKIEFILE     => "cookie.txt", // Set cookie file
        CURLOPT_COOKIEJAR      => "cookie.txt", // Set cookie jar
        CURLOPT_RETURNTRANSFER => true,     // Return web page
        CURLOPT_HEADER         => false,    // Don't return headers
        CURLOPT_FOLLOWLOCATION => true,     // Follow redirects
        CURLOPT_ENCODING       => "",       // Handle all encodings
        CURLOPT_AUTOREFERER    => true,     // Set referer on redirect
        CURLOPT_CONNECTTIMEOUT => 120,      // Timeout on connect
        CURLOPT_TIMEOUT        => 120,      // Timeout on response
        CURLOPT_MAXREDIRS      => 10,       // Stop after 10 redirects
    ];

    $ch = curl_init($url);
    curl_setopt_array($ch, $options);
    $content = curl_exec($ch);
    $err = curl_errno($ch);
    $errmsg = curl_error($ch);
    $header = curl_getinfo($ch);
    curl_close($ch);

    $header['errno'] = $err;
    $header['errmsg'] = $errmsg;
    $header['content'] = $content;
    return $header;
}

// Example of using the function to get a web page:
$result = get_web_page('https://www.example.com/page');

if ($result['errno'] != 0) {
    // Handle error: bad url, timeout, redirect loop
}

if ($result['http_code'] != 200) {
    // Handle error: no page, no permissions, no service
}

$page = $result['content'];</code>