Golang ファイルのアップロードで同時アップロードを処理するにはどうすればよいですか?

package main

import (
    "fmt"
    "io"
    "log"
    "net/http"
    "sync"
)

var maxConcurrency = 5
var filesToUpload = []string{"file1.txt", "file2.txt", "file3.txt"}

func main() {
    // 创建WaitGroup以跟踪同时上传的文件数量
    wg := sync.WaitGroup{}
    wg.Add(len(filesToUpload))

    // 创建用于通信的通道
    uploadQueue := make(chan string)

    for i := 0; i < maxConcurrency; i++ {
        go worker(uploadQueue, &wg)
    }

    // 将文件路径放入通道中
    for _, file := range filesToUpload {
        uploadQueue <- file
    }

    // 等待所有上传完成
    wg.Wait()

    fmt.Println("All files uploaded successfully")
}

func worker(uploadQueue chan string, wg *sync.WaitGroup) {
    for file := range uploadQueue {
        err := uploadFile(file)
        if err != nil {
            log.Printf("Error uploading file: %v", err)
        }
        wg.Done()
    }
}

func uploadFile(file string) error {
    // 打开文件
    f, err := os.Open(file)
    if err != nil {
        return err
    }

    // 准备HTTP请求
    req, err := http.NewRequest("POST", "http://localhost:8080/upload", f)
    if err != nil {
        return err
    }

    // 发送请求并关闭文件
    defer f.Close()
    resp, err := http.DefaultClient.Do(req)
    if err != nil {
        return err
    }

    defer resp.Body.Close()

    if resp.StatusCode != http.StatusOK {
        return fmt.Errorf("Upload failed with status code: %d", resp.StatusCode)
    }

    // 复制响应体以读取其内容
    buf := new(bytes.Buffer)
    if _, err := io.Copy(buf, resp.Body); err != nil {
        return err
    }

    // 处理响应内容
    fmt.Printf("File %s processed: %s\n", file, buf.String())

    return nil
}