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Q&A python operator precedence of in and comparison
python operator precedence of in and comparison
P粉848442185 2025-12-29 10:01:20 Views 70

0

The following comparisons produce True:

>>> '1' in '11'
True
>>> ('1' in '11') == True
True

And with the parentheses the other way, I get a TypeError:

>>> '1' in ('11' == True)
Traceback (most recent call last):
  File "", line 1, in 
TypeError: argument of type 'bool' is not iterable

So how do I get False with no parentheses?

>>> '1' in '11' == True
False
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