$data = [ '张三' => [ ['id'=>1,'name'=>1], ['id'=>2,'name'=>2], ['id'=>3,'name'=>3], ['id'=>1,'name'=>2] ], '李四' => [ ['id'=>1,'name'=>1], ['id'=>2,'name'=>2], ['id'=>3,'name'=>3], ['id'=>4,'name'=>4] ], '王五' => [ ['id'=>4,'name'=>4], ['id'=>5,'name'=>5], ['id'=>6,'name'=>6], ['id'=>7,'name'=>7] ] ]; function arr2Dict($arr) { $ret = array(); foreach($arr as $k=>$v){ $_id = $v['id']; if (array_key_exists($_id, $ret)) { $ret[$_id]++; }else{ $ret[$_id] = 1; } } return $ret; }; function compare($data, $a, $b) { $_a = arr2Dict($data[$a]); $_b = arr2Dict($data[$b]); foreach($_a as $k=>$v){ if(array_key_exists($k, $_b)) { echo "{$k} 在 {$a} 和 {$b} 重复\n"; } } }; compare($data, '张三', '李四'); compare($data, '张三', '王五'); compare($data, '李四', '王五');

====以下为老答案====

$data = array( array('id'=>1,'name'=>1), array('id'=>2,'name'=>2), array('id'=>3,'name'=>3), array('id'=>1,'name'=>2) ); $ret = array(); # 数据遍历一次，以计算重复key作为key新建数据，如果存在value +1，如果不存在设置为1 foreach($data as $k=>$v){ $_id = $v['id']; $_name = $v['name']; if (array_key_exists($_id, $ret)) { $ret[$_id]++; }else{ $ret[$_id] = 1; } } # 遍历结果 foreach($ret as $k=>$v){ echo "{$k}出现{$v}次\n"; } #print_r($id)