逻辑题：六个男人和六个女人,该怎么处理

$dict = array('A', 'B', 'C', 'D', 'E', 'F');<br />
<br />
//搜索 F太太成了C太太的儿媳妇的儿媳妇的儿媳妇的儿媳妇<br />
$st = array(<br />
	array('F' => 'A'),<br />
	array('F' => 'B'),<br />
	array('F' => 'C'),<br />
	array('F' => 'D'),<br />
	array('F' => 'E'),<br />
);<br />
<br />
while($rs = array_shift($st)) {<br />
	$len = count($rs);<br />
 	$k = end($rs);<br />
	if(isset($rs[$k])) continue;<br />
	foreach($dict as $v) {<br />
		if($k == $v <br><font color='#FF8000'>------解决方案--------------------</font><br> in_array($v, $rs)) continue;<br />
		if($len == 4 && $v == 'C') $res[] = array_merge($rs, array($k => $v));<br />
		else $st[] = array_merge($rs, array($k => $v));<br />
	}<br />
}<br />
//搜索结束，共 24 组<br />
<br />
foreach($res as $i=>$r) {<br />
	//配齐 6 个<br />
	$k = current(array_diff($dict, array_keys($r)));<br />
	$v = current(array_diff($dict, $r));<br />
	if($k == $v) continue;<br />
	$r = array_merge($r, array($k => $v));<br />
	//判断，两个条件不能同时满足<br />
	if($r[$r['B']] == 'A' && $r[$r[$r['D']]] == 'E') print_r($r);<br />
	//但分别可以<br />
//	if($r[$r['B']] == 'A') print_r($r); //A成了B的继父的继父<br />
//	if($r[$r[$r['D']]] == 'E') print_r($r); //D太太成了E太太的婆婆的婆婆的婆婆<br />
}<br />