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PHP接收json 并将接收数据插入数据库的实现代码

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Release: 2016-06-06 19:36:30
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这篇文章主要介绍了PHP接收json 并将接收数据插入数据库的实现代码,需要的朋友可以参考下

最近有一个需求,前端向后台提交json,后台解析并且将提交的值插入数据库中,
难点
1、php解析json(这个不算难点了,网上实例一抓一大把)
2、解析json后,php怎样拿到该拿的值

prepare($insert_order_product_sql); $result -> bind_param("sss", $order_id,$list_product_id[$i],$list_product_number[$i]); $result->execute(); } //--添加订单信息 $insert_order_sql="INSERT INTO tbl_order (order_id,buyer_id,seller_id,all_price) VALUES (?,?,?,?)"; $result=$sqlconn->prepare($insert_order_sql); $result->bind_param("ssss",$order_id,$buyer_id,$seller_id,$all_price); $result->execute(); $result -> close(); $sqlconn -> close(); ?>

投稿者信息
昵称: Hola
Email: jamcistos@outlook.com

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