After merging PHP arrays, how to check whether the merge is successful?-PHP Tutorial-php.cn

After merging PHP arrays, how to check whether the merge is successful?

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Release： 2024-04-28 15:54:02

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PHP 中检查数组合并是否成功的方法包括：（1）检查返回的数组是否为数组；（2）检查返回的数组长度是否等于预期长度。实战案例：合并两个员工数组，通过检查合并后数组长度是否等于预期值以判断合并是否成功。

After merging PHP arrays, how to check whether the merge is successful?

PHP 数组合并后检查合并是否成功的实用指南

在 PHP 中，我们可以使用 array_merge() 函数合并多个数组。但是，了解如何检查合并是否成功至关重要，以避免意外结果。

检查合并成功的方法

有两种常见的方法来检查数组合并是否成功：

检查返回的数组是否为数组：

$arr1 = [1, 2, 3];
$arr2 = [4, 5, 6];

$merged = array_merge($arr1, $arr2);

if (is_array($merged)) {
  // 合并成功
} else {
  // 合并失败
}

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检查返回的数组是否等于预期长度：

$length = count($arr1) + count($arr2);

$merged = array_merge($arr1, $arr2);

if (count($merged) == $length) {
  // 合并成功
} else {
  // 合并失败
}

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实战案例

在以下实战案例中，我们合并两个员工数组，每个数组包含员工的姓名和工资：

$employees1 = [
  ['name' => 'John', 'salary' => 1000],
  ['name' => 'Jane', 'salary' => 1200],
];

$employees2 = [
  ['name' => 'Mike', 'salary' => 900],
  ['name' => 'Alice', 'salary' => 1100],
];

$mergedEmployees = array_merge($employees1, $employees2);

if (count($mergedEmployees) == (count($employees1) + count($employees2))) {
  // 合并成功

  // 访问合并后的员工数据
  foreach ($mergedEmployees as $employee) {
    echo "{$employee['name']} earns \${$employee['salary']}\n";
  }
} else {
  // 合并失败，处理错误
}

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输出：

John earns $1000
Jane earns $1200
Mike earns $900
Alice earns $1100

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