Post binary data (application/octet stream)

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Release: 2024-02-05 21:15:28
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Post binary data (application/octet stream)

Question content

I want to upload a file with the content type set to application/octet-stream and the binary data of the file in the request body. How would I do this in golang, here is my starting code:

package main

import (
    "fmt"
    "log"
    "net/http"
    "net/http/httputil"
    "os"
)

func main() {
    file, err := os.Open("file.pdf")
    if err != nil {
        log.Fatalln(err)
    }

    req, err := http.NewRequest("POST", fmt.Sprintf("https://example.com/upload"), nil)
    req.Header.Add("Content-Type", "application/octet-stream")

    if err != nil {
        log.Fatalln(err)
    }

    client := &http.Client{
        Transport: &http.Transport{
            DisableCompression: true,
        },
    }

    resp, err := client.Do(req)
    if err != nil {
        log.Fatalln(err)
    }
    defer resp.Body.Close()

    reqDump, err := httputil.DumpRequest(req, true)
    if err != nil {
        log.Fatalln(err)
    }

    fmt.Println(reqDump)
}
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Correct answer


I put together an answer that may help you solve your problem. All code belongs to the main.go file and is just for demonstration. It has two main parts: handler and main functions. Let's start with the handler.

http handler

func handlefile(w http.responsewriter, r *http.request) {
    if r.method != http.methodpost {
        w.writeheader(http.statusmethodnotallowed)
        return
    }
    fmt.println("handlefile")
    data, err := io.readall(r.body)
    if err != nil {
        panic(err)
    }
    defer r.body.close()
    w.write(data)
}
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Here, I'm just relying on what you're using (go standard libraries only: http, io and fmt packages). We just need to write the incoming payload read from the http request to the response stream.

The main function

func main() {
    r := http.NewServeMux()
    r.HandleFunc("/example", HandleFile)
    srv := http.Server{
        Addr:    ":8000",
        Handler: r,
    }

    var wg sync.WaitGroup
    wg.Add(1)
    go func() {
        defer wg.Done()
        if err := srv.ListenAndServe(); err != nil {
            fmt.Println(err.Error())
        }
    }()

    file, err := os.Open("file.txt")
    if err != nil {
        panic(err)
    }
    defer file.Close()
    req, err := http.NewRequest(http.MethodPost, "http://localhost:8000/example", file)
    if err != nil {
        panic(err)
    }
    req.Header.Set("Content-Type", "application/octet-stream")
    client := &http.Client{
        Transport: &http.Transport{
            DisableCompression: true,
        },
    }
    res, err := client.Do(req)
    if err != nil {
        panic(err)
    }
    defer res.Body.Close()
    data, err := io.ReadAll(res.Body)
    if err != nil {
        panic(err)
    }
    fmt.Println(string(data))

    srv.Shutdown(context.Background())
    wg.Wait()
}
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In contrast, the main function has more logic to deal with. Let’s review them in the list:

  1. It creates an http server to serve incoming requests. We instrument it to reply to requests for the /example endpoint using the handlefile handler we created earlier.
  2. We use sync.waitgroup to run the server in a separate goroutine. Thanks to this, the server is up and running, but we can continue our program and send http requests within it.
  3. We prepare an http request containing the contents of a file read from the local file system (file.txt in our example). We set the content-type header to application/octet-stream and pass the file handle to the newrequest function.
  4. We make a request and print the contents of the http response payload.
  5. We shut down the server and use the wg.wait method to tell the waitgroup to wait for all goroutines.

Final considerations

The code written here can definitely be improved. Anyway, just for demonstration, I prefer to keep it as close to the original file as possible to give you a better understanding of how to publish binaries on an http server and how to run the same program both client and server. If there is anything unclear, please tell me, thank you!

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source:stackoverflow.com
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