Given an array of integer elements, the task is to remove duplicate values and print out the different elements in a sorted manner.
Given below is an array that stores integer type values in the order of 4, 6, 5, 3, 4, 5, 2, 8, 7 and 0. Now, the result will be 0, 2, 3 , 4, 4, 5, 5, 6, 7 and 8 print out the sorted elements in the order, but this result still contains duplicate values 4 and 5, they should be removed, the final result will be 0, 2, 3, 4, 5, 6, 7 and 8

Input: array[] = {4, 6, 5, 3, 4, 5, 2, 8, 7, 0}
Output: 0 2 3 4 5 6 7 8START
STEP 1: DECLARE VARIABLES i, j, array1[size], temp, count = 0
STEP 2: LOOP FOR i = 0 AND i < size AND i++
LOOP FOR j = i+1 AND j < size AND j++
IF array[i] == array[j]) then,
break
END IF
END FOR
IF j == size then,
ASSIGN array1[count++] WITH array[i]
END IF
END FOR
STEP 3: LOOP FOR i = 0 AND i < count-1 AND i++
LOOP FOR j = i+1 AND j < count AND j++
IF array1[i]>array1[j] then,
SWAP array1[i] AND array[j]
END IF
END FOR
END FOR
STEP 4: PRINT array1
STOP#include <stdio.h>
/* Prints distinct elements of an array */
void printDistinctElements(int array[], int size) {
int i, j, array1[size], temp, count = 0;
for(i = 0; i < size; i++) {
for(j = i+1; j < size; j++) {
if(array[i] == array[j]) {
/* Duplicate element found */
break;
}
}
/* If j is equal to size, it means we traversed whole
array and didn't found a duplicate of array[i] */
if(j == size) {
array1[count++] = array[i];
}
}
//sorting the array1 where only the distinct values are stored
for ( i = 0; i < count-1; i++) {
for ( j = i+1; j < count; j++) {
if(array1[i]>array1[j]) {
temp = array1[i];
array1[i] = array1[j];
array1[j] = temp;
}
}
}
for ( i = 0; i < count; ++i) {
printf("%d ", array1[i]);
}
}
int main() {
int array[] = {4, 6, 5, 3, 4, 5, 2, 8, 7, 0};
int n = sizeof(array)/sizeof(array[0]);
printDistinctElements(array, n);
return 0;
}0 2 3 4 5 6 7 8
The above is the detailed content of Print unique elements in a sorted array in C. For more information, please follow other related articles on the PHP Chinese website!