我们被给定一个整数'n',任务是生成六边形图案并显示最终输出。
Input-: n=5 Output-:
Input-: n = 4 Output-:
Approach we are using in the given program is as follows−
START Step 1-> declare function to print hexagonal pattern void pattern(int n) Declare and set int len = 2 * n - 1 Loop For int i = 0 and i < n and i++ declare and set int temp = i + n Loop For int k = 0 and k < temp and k++ IF ((k == n + i - 1) || (k == n - i - 1)) print * End Else print space End PrintEnd Loop For int m = 0 and m < n - 2 and m++ Loop For int j = 0 and j < len and j++ if (j == 0 || j == len - 1) Print * End Else print space End End Print
End declare and set int res = n - 1 Loop For int h = res and h >= 0 and h-- declare and set int temp2 = h + n Loop For int k = 0 and k < temp2 and k++ if ((k == n + h - 1) || (k == n - h - 1)) print * End Else print space End End Print
End End Step 2-> In main() Declare variable int n = 5 call pattern(n) STOP
#include//program to print hexagon pattern void pattern(int n) { int len = 2 * n - 1; //for loop for upper part of a pattern for (int i = 0; i < n; i++) { int temp = i + n; for (int k = 0; k < temp; k++) { if ((k == n + i - 1) || (k == n - i - 1)) printf("*"); else printf(" "); } printf(" "); } //for loop for mid part of a pattern for (int m = 0; m < n - 2; m++) { for (int j = 0; j < len; j++) { if (j == 0 || j == len - 1) printf("*"); else printf(" "); } printf("
"); } //for loop for lower part of a pattern int res = n - 1; for (int h = res; h >= 0; h--) { int temp2 = h + n; for (int k = 0; k < temp2; k++) { if ((k == n + h - 1) || (k == n - h - 1)) printf("*"); else printf(" "); } printf("
"); } } int main() { int n = 5; pattern(n); return 0; }
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