How to sort one list based on the value of another list in Python?-Python Tutorial-php.cn

How to sort one list based on the value of another list in Python?

We can sort a list by the values in another list by setting the second list to the index number of the value in the first list in sorted order .

Sort a list by values in another list

Example

In this example, we will sort the list based on the values in another list, i.e. the indexes of the second list will be in the order they are placed in the sorted order -

# Two Lists list1 = ['BMW', 'Toyota', 'Audi', 'Tesla', 'Hyundai'] list2 = [2, 5, 1, 4, 3] print("List1 = \n",list1) print("List2 (indexes) = \n",list2) # Sorting the List1 based on List2 res = [val for (_, val) in sorted(zip(list2, list1), key=lambda x: x[0])] print("\nSorted List = ",res)

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Output

List1 = ['BMW', 'Toyota', 'Audi', 'Tesla', 'Hyundai'] List2 (indexes) = [2, 5, 1, 4, 3] Sorted List = ['Audi', 'BMW', 'Hyundai', 'Tesla', 'Toyota']

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Use a dictionary to sort a list by values in another list

Example

In this example, we will sort one list by the value of another list. We add these two lists to a dictionary and then sort them using the key values and lambdas in the dictionary.

# Two Lists list1 = ['BMW', 'Toyota', 'Audi', 'Tesla', 'Hyundai'] list2 = [2, 5, 1, 4, 3] print("List1 = \n",list1) print("List2 (indexes) = \n",list2) # Blank dictionary newDict = {} # Blank list outList = [] # Both the lists in our dictionary newDict newDict = {list1[i]: list2[i] for i in range(len(list2))} # Sorting using the sorting() based on key and values # Using lambda as well s = {k: v for k, v in sorted(newDict.items(), key=lambda item: item[1])} # Element addition in the list for i in s.keys(): outList.append(i) print("\nSorted List = \n",outList)

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Output

List1 = ['BMW', 'Toyota', 'Audi', 'Tesla', 'Hyundai'] List2 (indexes) = [2, 5, 1, 4, 3] Sorted List = ['Audi', 'BMW', 'Hyundai', 'Tesla', 'Toyota']

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