Translate the following into Chinese: C program to convert decimal to binary decimal

Consider the following example to understand how to convert decimal to binary decimal in C programming language.

Example 1- Convert 25 to binary.

Step 1 - 25 / 2 Remainder: 1, quotient: 12

Step 2 - 12 / 2 Remainder: 0, quotient: 6

Step 3 - 6 / 2 Remainder: 0, quotient: 3

Step 4 - 3 / 2 Remainder: 1, quotient: 1

Step 5 - 1 / 2 Remainder: 1, quotient: 0

Thus, the equivalent binary number is: 11001

Example 2- Convert 0.7 to binary.

Step 1 - 0.7 * 2 = 1.4, integer part = 1

Step 2 - 0.4 * 2 = 0.8, integer part = 0

Step 3 - 0.8 * 2 = 1.6, integer part = 1

Step 4 - 0.6 * 2 = 1.2, integer part = 1

Step 5 - 0.2 * 2 = 0.4, integer part = 0

Step 6 - 0.4 * 2 = 0.8, integer part = 0

So, the equivalent binary number is: 0.101100

Step 3 - Finally, the binary value of the decimal number 25.7 is as follows:

11001 + 0.101100 = 1101.101100

Example

The following is a C program to convert a decimal decimal to a binary decimal:

Real-time demonstration

#include int main(){ long double fraDecimal,fraBinary,bFractional = 0.0,dFractional,fraFactor=0.1; long int dIntegral,bIntegral=0; long int intFactor=1,remainder,temp,i; printf("Enter any fractional decimal number: "); scanf("%Lf",&fraDecimal); dIntegral = fraDecimal; dFractional = fraDecimal - dIntegral; while(dIntegral!=0){ remainder=dIntegral%2; bIntegral=bIntegral+remainder*intFactor; dIntegral=dIntegral/2; intFactor=intFactor*10; } for(i=1;i<=6;i++){ dFractional = dFractional * 2; temp = dFractional; bFractional = bFractional + fraFactor* temp; if(temp ==1) dFractional = dFractional - temp; fraFactor=fraFactor/10; } fraBinary = bIntegral + bFractional; printf("Equivalent binary value: %lf",fraBinary); return 0; }

Output

When executed When executing the above program, the following results will be produced -

Enter any fractional decimal number: 5.7 Equivalent binary value: 101.101100

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