SELECTSTRCMP("demo","demo");The following is the output of the above query. +------------------------+|STRCMP("demo""> How to check similarity between two strings in MySQL?-Mysql Tutorial-php.cn

How to check similarity between two strings in MySQL?

王林
Release: 2023-09-02 21:01:06
forward
1570 people have browsed it

How to check similarity between two strings in MySQL?

You can check the similarity between two strings with the help of "strcmp()" function. The conditions are as follows.

  • If the two strings are equal, 0 is returned.

  • If the first strings are equal, 0 is returned. If the string is less than the second string, -1 is returned.

  • If the first string is greater than the second string, return 1.

  • This is an example.

    Case 1- If two strings are equal.

    The following is the query.

    mysql > SELECT STRCMP("demo", "demo");
    Copy after login

    The following is the output of the above query.

    +------------------------+ | STRCMP("demo", "demo") | +------------------------+ | 0 | +------------------------+ 1 row in set (0.00 sec)
    Copy after login

    Case 2- If the first string is less than the second string.

    The following is the query.

    mysql> SELECT STRCMP("demo", "demo1234");
    Copy after login

    The following is the output of the above query.

    +----------------------------+ | STRCMP("demo", "demo1234") | +----------------------------+ | -1 | +----------------------------+ 1 row in set (0.00 sec)
    Copy after login

    Case 3- If the first string is greater than the second string.

    The following is the query.

    mysql> SELECT STRCMP("demo1", "demo");
    Copy after login

    The following is the output.

    +-------------------------+ | STRCMP("demo1", "demo") | +-------------------------+ | 1 | +-------------------------+ 1 row in set (0.00 sec)
    Copy after login

The above is the detailed content of How to check similarity between two strings in MySQL?. For more information, please follow other related articles on the PHP Chinese website!

source:tutorialspoint.com
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!