Write a C program to convert a given number of days into years, weeks and days

Given the number of days, the task is to convert the given number of days into years, weeks and days.

Let us assume the number of days in a year = 365

Number of years = (number of days)/365

Explanation-: The number of years will be divided by giving The quotient of a given number of days and 365

number of weeks = (number of days % 365) / 7

Explanation-: The number of weeks will be obtained by collecting the remainder and dividing the number of days by 365 , divided by the number of days in the week, 7.

Number of days = (Number of days % 365) % 7

Explanation-: The number of days is the remainder obtained by dividing the number of days by 365 and then dividing the remainder by the number of days in the week 7 .

Example

Input-:days = 209 Output-: years = 0 weeks = 29 days = 6 Input-: days = 1000 Output-: years = 2 weeks = 38 days = 4

Algorithm

Start Step 1-> declare macro for number of days as const int n=7 Step 2-> Declare function to convert number of days in terms of Years, Weeks and Days void find(int total_days) declare variables as int year, weeks, days Set year = total_days / 365 Set weeks = (total_days % 365) / n Set days = (total_days % 365) % n Print year, weeks and days Step 3-> in main() Declare int Total_days = 209 Call find(Total_days) Stop

Example

Live demonstration

#include  const int n=7 ; //find year, week, days void find(int total_days) { int year, weeks, days; // assuming its not a leap year year = total_days / 365; weeks = (total_days % 365) / n; days = (total_days % 365) % n; printf("years = %d",year); printf("
weeks = %d", weeks); printf("
days = %d ",days); } int main() { int Total_days = 209; find(Total_days); return 0; }

Output

If we run the above code , it will generate the following output

years = 0 weeks = 29 days = 6

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