C program to calculate distance between three points in 3D space

Given a three-dimensional plane and therefore three coordinates, the task is to find the distance between the given points and display the result.

On the three-dimensional plane, there are three coordinate axes. The coordinates of the x-axis are (x1, y1, z1), the coordinates of the y-axis are (x2, y2, z2), and the coordinates of the z-axis are (x3, y3,z). There is a direct formula for calculating the distance between them as follows

$$\sqrt{\lgroup x2-x1\rgroup^{2} \lgroup y2-y1\rgroup^{2} \lgroup z2 -z1\rgroup^{2}}$$

The following is a diagram showing three different axes and their coordinates

The method used below is as follows−

• Input coordinates (x1, y1, z1), (x2, y2, z2) and (x3, y3, z3)
• Apply the formula to calculate the difference between these points
• Print distance

Algorithm

Start Step 1-> declare function to calculate distance between three point void three_dis(float x1, float y1, float z1, float x2, float y2, float z2) set float dis = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2) + pow(z2 - z1, 2) * 1.0) print dis step 2-> In main() Set float x1 = 4 Set float y1 = 9 Set float z1 = -3 Set float x2 = 5 Set float y2 = 10 Set float z2 = 9 Call three_dis(x1, y1, z1, x2, y2, z2) Stop

Example

Example

#include  #include //function to find distance bewteen 3 point void three_dis(float x1, float y1, float z1, float x2, float y2, float z2) { float dis = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2) + pow(z2 - z1, 2) * 1.0); printf("Distance between 3 points are : %f", dis); return; } int main() { float x1 = 4; float y1 = 9; float z1 = -3; float x2 = 5; float y2 = 10; float z2 = 9; three_dis(x1, y1, z1, x2, y2, z2); return 0; }

Output

If we run the above code it will generate the following output

Distance between 3 points are : 12.083046

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