How to replace array name with something else in php

PHPz
Release: 2023-04-19 13:45:37
Original
490 people have browsed it

In PHP, if you want to replace the array name with something else, you can use some simple methods and techniques. This article will introduce some commonly used methods and techniques for your reference.

1. Replace the array name with another array

1. Use the array_combine() function

array_combine() function to merge two arrays into a new association array. Using this function, you can replace the keys in one array with the keys in another array.

Sample code:

$array1 = array('a', 'b', 'c');
$array2 = array('1', '2', '3');

$newArray = array_combine($array2, $array1);

print_r($newArray);
Copy after login

Output:

Array (
  [1] => a
  [2] => b
  [3] => c
)
Copy after login

In the above example, the key names in the $array1 array will be replaced with the key names in the $array2 array.

2. Use the array_replace() function

The array_replace() function can replace the values ​​in one array with the values ​​in another array. Using this function, you can replace the keys in one array with the keys in another array.

Sample code:

$array1 = array('a' => '1', 'b' => '2', 'c' => '3');
$array2 = array('a' => 'one', 'b' => 'two', 'c' => 'three');

$newArray = array_replace($array1, $array2);

print_r($newArray);
Copy after login

Output:

Array (
  [a] => one
  [b] => two
  [c] => three
)
Copy after login

In the above example, the key names in the $array1 array will be replaced with the key names in the $array2 array.

2. Replace the array name with a variable name

1. Use the $$ symbol

In PHP, you can use the $$ symbol to replace the array name with a variable name. The $$ symbol is followed by a string, which is the variable name to be replaced, which can be a custom variable name or the variable name of other global variables or local variables.

Sample code:

$person = array('name' => '张三', 'age' => 20, 'gender' => '男');

$field = 'gender';

echo $$field; // 输出:男
Copy after login

In the above example, the 'gender' key name in the $person array is replaced with the $field variable name, and the value of the variable 'male' is finally output.

2. Use the extract() function

The extract() function can import the key-value pairs in the associative array into the current symbol table as variable names and variable values. Using this function, you can replace an array name with the corresponding variable name.

Sample code:

$person = array('name' => '张三', 'age' => 20, 'gender' => '男');

extract($person);

echo $gender; // 输出:男
Copy after login

In the above example, the extract() function is used to replace the key name in the $person array with the variable name, so the value of the $gender variable can be directly output 'Male' '.

3. Replace the array name with the object attribute

In PHP, you can replace an array name with the corresponding object attribute name, so that you can access the object's attribute value.

Sample code:

class Person {
  public $name;
  public $age;
  public $gender;

  public function __construct($personData) {
    $this->name = $personData['name'];
    $this->age = $personData['age'];
    $this->gender = $personData['gender'];
  }
}

$personData = array('name' => '张三', 'age' => 20, 'gender' => '男');

$person = new Person($personData);

echo $person->gender; // 输出:男
Copy after login

In the above example, the $personData array name is replaced with the property name of the $person object, so that the property value of the object can be accessed.

Summary

The above are several commonly used PHP array name replacement methods and techniques. You can choose the appropriate method according to the actual situation. When using these methods, pay attention to the detailed handling of arrays or objects to avoid unexpected errors.

The above is the detailed content of How to replace array name with something else in php. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!