Method 1: Use the substr_count() function
a. Grammar format:
substr_count(string,substring,start,length)
string: The string being checked.
#substring: The string to search for.
#start: Specifies where to start searching in the string. (Optional)
#length: Specifies the length of the search. (Optional)
Return value: Returns the number of times the substring appears in the string.
b. Example:
"; $key1='com'; if (substr_count($url, $key1) == false) echo 'URL中不存在子字符串 '.$key1.'
' ; else echo 'URL中存在 '.$key1.'
' ; ?>
c. Output:
URL中存在子字符串cn URL中不存在 com
Method 2: Use the strpos() function
a. Syntax format:
strpos(string,find,start)
string The string to be searched.
#find The string to be found.
#start Where to start the search. (Optional)
Return value: Find the first occurrence of a string in another string.
ps: The strpos() function is case-sensitive.
b.Example:
' ; } else { echo 'URL中存在子字符串 '.$key.'
' ; } echo "
"; $key1 = 'com'; if (strpos($url, $key1) == false) { echo 'URL中不存在子字符串 '.$key1; } else { echo 'URL中存在子字符串 '.$key1 ; } ?>
c.Output:
URL中存在子字符串 cn URL中不存在子字符串 com
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