Implement Ajax file upload function

Ajax Tutorialcolumn shares the specific code for Ajax file upload for your reference. The specific content is as follows

Front-end form and JQuery jsp/html code

Using JQury

Front-end form

 
请选择要上传的文件：
 
 
 

ajax request server

Conroller.java

@PostMapping("/upload") public void fileUpload2(@RequestParam("file") CommonsMultipartFile file, HttpServletRequest request) throws IOException { System.out.println("走了"); //上传路径保存设置 String path = request.getServletContext().getRealPath("/upload"); File realPath = new File(path); if (!realPath.exists()) { realPath.mkdir(); } //上传文件地址 System.out.println("上传文件保存地址：" + realPath); //通过CommonsMultipartFile的方法直接写文件（注意这个时候） file.transferTo(new File(realPath + "/" + file.getOriginalFilename())); }

Result

The above is the entire content of this article, I hope it will be helpful to everyone's study.

Related free learning recommendations:javascript(video)

The above is the detailed content of Implement Ajax file upload function. For more information, please follow other related articles on the PHP Chinese website!