How to replace Chinese and English symbols in php?

coldplay.xixi
Release: 2023-03-02 09:56:01
Original
3314 people have browsed it

php Chinese and English symbol replacement method: 1. Simple replacement, the code is [$val1=str_replace(',',',',$val1);]; 2. All character replacement, that is, regular replacement , the code is [c[i]=(char)(c[i]-65248);].

How to replace Chinese and English symbols in php?

How to replace Chinese and English symbols in php:

1. Summary of methods

Method 1: Simple replacement (php code)

$val1=str_replace(',',',',$val1); $val1=str_replace('(','(',$val1); $val1=str_replace(')',')',$val1);
Copy after login
Copy after login

Method 2: Replace all characters (regular replacement)

for (int i = 0; i < c.Length; i++) { if (c[i]==12288) { c[i]= (char)32; continue; } if (c[i]>65280 && c[i]<65375) c[i]=(char)(c[i]-65248); }
Copy after login

2. Replace Chinese punctuation marks Into English punctuation marks

Simple replacement (php code)

$val1=str_replace(',',',',$val1); $val1=str_replace('(','(',$val1); $val1=str_replace(')',')',$val1);
Copy after login
Copy after login
/// 转全角的函数(SBC case) /// ///任意字符串 /// 全角字符串 /// ///全角空格为12288,半角空格为32 ///其他字符半角(33-126)与全角(65281-65374)的对应关系是:均相差65248 /// public string ToSBC(string input) { //半角转全角: char[] c=input.ToCharArray(); for (int i = 0; i < c.Length; i++) { if (c[i]==32) { c[i]=(char)12288; continue; } if (c[i]<127) c[i]=(char)(c[i]+65248); } return new string(c); } /// /// 转半角的函数(DBC case) /// ///任意字符串 /// 半角字符串 /// ///全角空格为12288,半角空格为32 ///其他字符半角(33-126)与全角(65281-65374)的对应关系是:均相差65248 /// public string ToDBC(string input) { char[] c=input.ToCharArray(); for (int i = 0; i < c.Length; i++) { if (c[i]==12288) { c[i]= (char)32; continue; } if (c[i]>65280 && c[i]<65375) c[i]=(char)(c[i]-65248); } return new string(c); }
Copy after login

Related learning recommendations:PHP programming from entry to proficiency

The above is the detailed content of How to replace Chinese and English symbols in php?. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!