How to simply output the current date and time in C++

Recommended study: "c Tutorial"

First introduce the 2 data types.

One is time_t, A variable related to the time function. The defined variable records the number of seconds that have passed since January 1, 1970, also known as timestamp.

The other is the structuretm,

struct tm
{
   int tm_sec;         // 秒，范围从 0 到 59
   int tm_min;         // 分，范围从 0 到 59
   int tm_hour;        // 小时，范围从 0 到 23
   int tm_mday;        // 一月中的第几天，范围从 1 到 31
   int tm_mon;         // 月份，范围从 0 到 11
   int tm_year;        // 自 1900 起的年数
   int tm_wday;        // 一周中的第几天，范围从 0 到 6
   int tm_yday;        // 一年中的第几天，范围从 0 到 365
   int tm_isdst;       // 夏令时
};

Then there are three functions related to time processing,

time_t time(time_t *time);

Generally, time(NULL) can be used to get the timestamp of the current time zone.

struct tm *localtime(const time_t *timer);

Convert time_t type to pointer of tm structure of local time.

size_t strftime(char *str, size_t maxsize, const char *format, const struct tm *timeptr)

str -- This is a pointer to the destination array to which the resulting C string will be copied.

maxsize -- This is the maximum number of characters to be copied to str.

format -- This is a C string containing any combination of ordinary characters and special format specifiers. These format specifiers are replaced by the function with corresponding values ​​representing the times specified in tm.

Format specifier:

4行代码实现在屏幕输出当前时间：

char str[50];
time_t now = time(NULL);
strftime(str, 50, "%x %X", localtime(&now));
cout << str << endl;

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