How to determine whether an element is in an array in java-JavaBase-php.cn

How to determine whether an element is in an array in java

How to determine whether an element exists in an array in java:

1. Convert the array into a List, and then use the contains in the List to determine whether it exists.

public static boolean useList(String[] arr,String containValue){ return Arrays.asList(arr).contains(containValue); }

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It should be noted that the List converted in the Arrays.asList method is not java.util.ArrayList but java.util.Arrays.ArrayList. Arrays cannot be converted in java.util.Arrays.ArrayList. The length is particularly important for expansion operations. The contains implementation is as follows:

@Override public boolean contains(Object o) { //调用indexOf方法判断其在那个位置，判断其时候为-1 return indexOf(o) != -1; } @Override public int indexOf(Object o) { //获取元素 E[] a = this.a; //判断空 if (o == null) { //循环判断 for (int i = 0; i < a.length; i++) //如果元素为null if (a[i] == null) //则返回 return i; } else { //如果其不为空 for (int i = 0; i < a.length; i++) //判断元素与a[i]是否相等 if (o.equals(a[i])) //相等返回i return i; } //否则返回-1 return -1; }

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2. Use Set to implement to determine whether it exists

public static boolean useSet(String[] arr,String containValue){ return new HashSet<>(Arrays.asList(arr)).contains(containValue); }

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3. Use loops to implement

public static boolean useLoop(String[] arr,String containValue){ //判断是否为空 if (arr==null||arr.length==0){ return false; } for (int i = 0; i < arr.length; i++) { //all null if (containValue!=null&&containValue.equals(arr[i])){ return true; }else if (arr[i]==null){ return true; } } return false; }

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4. Use the contains method in org.apache.commons.lang3.ArrayUtils to implement

public static boolean useUtils(String[] arr,String containValue){ return ArrayUtils.contains(arr,containValue); }

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Implementation code:

public static boolean contains(final Object[] array, final Object objectToFind) { //调用indexof进行判断位置 return indexOf(array, objectToFind) != INDEX_NOT_FOUND; } public static int indexOf(final Object[] array, final Object objectToFind, int startIndex) { //判断null if (array == null) { return INDEX_NOT_FOUND; } //判断起始位置 if (startIndex < 0) { startIndex = 0; } //判断查询元素是否为null if (objectToFind == null) { //null则直接使用==进行循环判断位置 for (int i = startIndex; i < array.length; i++) { if (array[i] == null) { return i; } } //判断元素是不是array中的元素的实例，如果是则循环并采用equals进行判断 } else if (array.getClass().getComponentType().isInstance(objectToFind)) { for (int i = startIndex; i < array.length; i++) { if (objectToFind.equals(array[i])) { return i; } } } //返回没有找到 return INDEX_NOT_FOUND; }

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For more java knowledge, please pay attention tojava basic tutorial.

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