java.io.File.isFile() Checks whether the file representing this abstract pathname is a normal file.
Indicates that the file of this abstract path name is a file, this method returns true, otherwise this method returns false.
Exception to .lang.String) method denies read access to the file
Example
The following example demonstrates the usage of the java.io.File.isFile() method . package com.test;
import java.io.File;
public class FileDemo {
public static void main(String[] args) {
File f = null;
String path;
boolean bool = false;
try{
// create new file
f = new File("c:");
// true if the file path is a file, else false
bool = f.isFile();
// get the path
path = f.getPath();
// prints
System.out.println(path+" is file? "+ bool);
// create new file
f = new File("c:/test.txt");
// true if the file path is a file, else false
bool = f.isFile();
// get the path
path = f.getPath();
// prints
System.out.print(path+" is file? "+bool);
}catch(Exception e){
// if any error occurs
e.printStackTrace();
}
}
}
c: is file? false c:est.txt is file? true
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