How to get the current file path in python

Python method to get the current path:

import os,sys

Use sys.path[0], sys.argv[0], os.getcwd(), os.path.abspath(__file__), os.path.realpath(__file__)

sys.path is a list of search paths that Python will use to find modules, sys.path[0] and sys.argv[0] is the same thing because Python will automatically add sys.argv[0] to sys.path.

If you execute python getpath\getpath.py in the C:\test directory, then os.getcwd() will output "C:\test" and sys.path[0] will output "C:\ test\getpath".

If you use the py2exe module to compile a Python script into an executable file, the output of sys.path[0] will also change:
If the dependent library is packaged as a zip file in the default way, then sys.path[0] will output "C:\test\getpath\libarary.zip";
If the zipfile=None parameter is specified in setup.py, the dependent library will be packaged into the exe file, then sys. path[0] will output "C:\test\getpath\getpath.exe".

#!/bin/env python #-*- encoding=utf8 -*- import os,sys if __name__=="__main__": print "__file__=%s" % __file__ print "os.path.realpath(__file__)=%s" % os.path.realpath(__file__) print "os.path.dirname(os.path.realpath(__file__))=%s" % os.path.dirname(os.path.realpath(__file__)) 　　 print "os.path.split(os.path.realpath(__file__))=%s" % os.path.split(os.path.realpath(__file__))[0]　　 print "os.path.abspath(__file__)=%s" % os.path.abspath(__file__) print "os.getcwd()=%s" % os.getcwd() print "sys.path[0]=%s" % sys.path[0] print "sys.argv[0]=%s" % sys.argv[0] 输出结果: D:\>python ./python_test/test_path.py __file__=./python_test/test_path.py os.path.realpath(__file__)=D:\python_test\test_path.py os.path.dirname(os.path.realpath(__file__))=D:\python_test os.path.split(os.path.realpath(__file__))=D:\python_test os.path.abspath(__file__)=D:\python_test\test_path.py os.getcwd()=D:\ sys.path[0]=D:\python_test sys.argv[0]=./python_test/test_path.py

os.getcwd() "D:\", the starting execution directory is taken
sys.path[0] or sys.argv[0] "D:\python_test", taken It is the directory where the initially executed script is located
os.path.split(os.path.realpath(__file__))[0] "D:\python_test", which takes the location of the file test_path.py where __file__ is located Directory

Correctly obtain the current path:

__file__是当前执行的文件 # 获取当前文件__file__的路径 print "os.path.realpath(__file__)=%s" % os.path.realpath(__file__) # 获取当前文件__file__的所在目录 print "os.path.dirname(os.path.realpath(__file__))=%s" % os.path.dirname(os.path.realpath(__file__)) 　　 # 获取当前文件__file__的所在目录 print "os.path.split(os.path.realpath(__file__))=%s" % os.path.split(os.path.realpath(__file__))[0]　

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