1. Avoid using complex expressions in loop conditions
Without compilation optimization, the loop condition will be repeated in the loop Calculation, if you do not use complex expressions and keep the loop condition value unchanged, the program will run faster.
Example:
import java.util.vector; class cel { void method (vector vector) { for (int i = 0; i < vector.size (); i++) // violation ; // ... } }
Correction:
class cel_fixed { void method (vector vector) { int size = vector.size () for (int i = 0; i < size; i++) ; // ... } }
## 2. For 'vectors ' and 'hashtables' define the initial size
When jvm expands the size of vector, it needs to re-create a larger array and copy the contents of the original array. Finally, the original The array is recycled again. It can be seen that the expansion of vector capacity is a time-consuming matter.
Usually, the default 10 element size is not enough. You'd better make an accurate estimate of the optimal size you need.
Example:
import java.util.vector; public class dic { public void addobjects (object[] o) { // if length > 10, vector needs to expand for (int i = 0; i< o.length;i++) { v.add(o); // capacity before it can add more elements. } } public vector v = new vector(); // no initialcapacity. }
Correction:
Set the initial size yourself.
public vector v = new vector(20); public hashtable hash = new hashtable(10);
3. Close the stream in the finally block
The resources used in the program should be released to avoid resource leaks . This is best done in a finally block. Regardless of the result of program execution, the finally block will always be executed to ensure that the resource is closed correctly.
Example:
import java.io.*; public class cs { public static void main (string args[]) { cs cs = new cs (); cs.method (); } public void method () { try { fileinputstream fis = new fileinputstream ("cs.java"); int count = 0; while (fis.read () != -1) count++; system.out.println (count); fis.close (); } catch (filenotfoundexception e1) { } catch (ioexception e2) { } } }
Add a finally block after the last catch
4. Use 'system. arraycopy ()' instead of copying an array through a loop
'system.arraycopy ()' is much faster than copying an array through a loop.
Example:
public class irb { void method () { int[] array1 = new int [100]; for (int i = 0; i < array1.length; i++) { array1 [i] = i; } int[] array2 = new int [100]; for (int i = 0; i < array2.length; i++) { array2 [i] = array1 [i]; // violation } } }
Correction:
public class irb { void method () { int[] array1 = new int [100]; for (int i = 0; i < array1.length; i++) { array1 [i] = i; } int[] array2 = new int [100]; system.arraycopy(array1, 0, array2, 0, 100); } }
5. Let the getter/setter access the variables within the instance The method becomes "final"
Simple getter/setter methods should be made final. This will tell the compiler that this method will not be overloaded, so it can become " inlined”
Example:
class maf { public void setsize (int size) { _size = size; } private int _size; }
class daf_fixed { final public void setsize (int size) { _size = size; } private int _size; }
6. Avoid unnecessary instanceof operations
If the static type of the object on the left is equal to the one on the right, the instanceof expression will always return true.
Example:
public class uiso { public uiso () {} } class dog extends uiso { void method (dog dog, uiso u) { dog d = dog; if (d instanceof uiso) // always true. system.out.println("dog is a uiso"); uiso uiso = u; if (uiso instanceof object) // always true. system.out.println("uiso is an object"); } }
Delete the unnecessary instanceof operation.
class dog extends uiso { void method () { dog d; system.out.println ("dog is an uiso"); system.out.println ("uiso is an uiso"); } }
7. Avoid unnecessary styling operations
All classes are directly or indirectly inherited from object . Likewise, all subclasses are implicitly "equal" to their parent class. Then, the operation of modeling from the subclass to the parent class is unnecessary.
Example:
class unc { string _id = "unc"; } class dog extends unc { void method () { dog dog = new dog (); unc animal = (unc)dog; // not necessary. object o = (object)dog; // not necessary. } }
class dog extends unc { void method () { dog dog = new dog(); unc animal = dog; object o = dog; } }
8. If you are only looking for a single character, use charat() instead of startswith()
Calling startswith() with one character as a parameter will also work well, but from a performance perspective, calling the string API is undoubtedly wrong!
Example:
public class pcts { private void method(string s) { if (s.startswith("a")) { // violation // ... } } }
Replace 'startswith()' with 'charat()'.
public class pcts { private void method(string s) { if ('a' == s.charat(0)) { // ... } } }
9 , Use shift operations instead of 'a / b' operations
"/" is a very "expensive" operation, using shift operations will be faster and more efficient.
Example:
public class sp { public static final int num = 16; public void calculate(int a) { int p = a / 4; // should be replaced with "a >> 2". int p2 = a / 8; // should be replaced with "a >> 3". int temp = a / 3; } }
public class sp { public static final int num = 16; public void calculate(int a) { int p = a >> 2; int p2 = a >> 3; int temp = a / 3; // 不能转换成位移操作 } }
10. Use shift operation instead of 'a * b'
Same as above.
[i]But I personally think that this method should only be used unless it is within a very large loop, performance is very important, and you know what you are doing. Otherwise, it will be uneconomical to reduce the readability of the program caused by improving performance.
Example:
public class smul { public void calculate(int a) { int mul = a * 4; // should be replaced with "a << 2". int mul2 = 8 * a; // should be replaced with "a << 3". int temp = a * 3; } }
package opt; public class smul { public void calculate(int a) { int mul = a << 2; int mul2 = a << 3; int temp = a * 3; // 不能转换 } }
11. When adding strings, use ' ' Replace " " if the string has only one character
Example:
public class str { public void method(string s) { string string = s + "d" // violation. string = "abc" + "d" // violation. } }
Correction:
Convert a one-character string Replace with ' '
public class str { public void method(string s) { string string = s + 'd' string = "abc" + 'd' } }
十二、不要在循环中调用synchronized(同步)方法
方法的同步需要消耗相当大的资料,在一个循环中调用它绝对不是一个好主意。
例子:
import java.util.vector; public class syn { public synchronized void method (object o) { } private void test () { for (int i = 0; i < vector.size(); i++) { method (vector.elementat(i)); // violation } } private vector vector = new vector (5, 5); }
更正:
不要在循环体中调用同步方法,如果必须同步的话,推荐以下方式:
import java.util.vector; public class syn { public void method (object o) { } private void test () { synchronized{//在一个同步块中执行非同步方法 for (int i = 0; i < vector.size(); i++) { method (vector.elementat(i)); } } } private vector vector = new vector (5, 5); }
十三、将try/catch块移出循环
把try/catch块放入循环体内,会极大的影响性能,如果编译jit被关闭或者你所使用的是一个不带jit的jvm,性能会将下降21%之多!
例子:
import java.io.fileinputstream; public class try { void method (fileinputstream fis) { for (int i = 0; i < size; i++) { try { // violation _sum += fis.read(); } catch (exception e) {} } } private int _sum; }
更正:
将try/catch块移出循环
void method (fileinputstream fis) { try { for (int i = 0; i < size; i++) { _sum += fis.read(); } } catch (exception e) {} }
十四、对于boolean值,避免不必要的等式判断
将一个boolean值与一个true比较是一个恒等操作(直接返回该boolean变量的值). 移走对于boolean的不必要操作至少会带来2个好处:
1)代码执行的更快 (生成的字节码少了5个字节);
2)代码也会更加干净 。
例子:
public class ueq { boolean method (string string) { return string.endswith ("a") == true; // violation } }
更正:
class ueq_fixed { boolean method (string string) { return string.endswith ("a"); } }
十五、对于常量字符串,用'string' 代替 'stringbuffer'
常量字符串并不需要动态改变长度。
例子:
public class usc { string method () { stringbuffer s = new stringbuffer ("hello"); string t = s + "world!"; return t; } }
更正:
把stringbuffer换成string,如果确定这个string不会再变的话,这将会减少运行开销提高性能。
十六、用'stringtokenizer' 代替 'indexof()' 和'substring()'
字符串的分析在很多应用中都是常见的。使用indexof()和substring()来分析字符串容易导致 stringindexoutofboundsexception。而使用stringtokenizer类来分析字符串则会容易一些,效率也会高一些。
例子:
public class ust { void parsestring(string string) { int index = 0; while ((index = string.indexof(".", index)) != -1) { system.out.println (string.substring(index, string.length())); } } }
十七、使用条件操作符替代"if (cond) return; else return;" 结构
条件操作符更加的简捷
例子:
public class if { public int method(boolean isdone) { if (isdone) { return 0; } else { return 10; } } }
更正:
public class if { public int method(boolean isdone) { return (isdone ? 0 : 10); } }
十八、使用条件操作符代替"if (cond) a = b; else a = c;" 结构
例子:
public class ifas { void method(boolean istrue) { if (istrue) { _value = 0; } else { _value = 1; } } private int _value = 0; }
更正:
public class ifas { void method(boolean istrue) { _value = (istrue ? 0 : 1); // compact expression. } private int _value = 0; }
十九、不要在循环体中实例化变量
在循环体中实例化临时变量将会增加内存消耗
例子:
import java.util.vector; public class loop { void method (vector v) { for (int i=0;i < v.size();i++) { object o = new object(); o = v.elementat(i); } } }
更正:
在循环体外定义变量,并反复使用
import java.util.vector; public class loop { void method (vector v) { object o; for (int i=0;i Copy after login
二十、确定 stringbuffer的容量
stringbuffer的构造器会创建一个默认大小(通常是16)的字符数组。在使用中,如果超出这个大小,就会重新分配内存,创建一个更大的数组,并将原先的数组复制过来,再丢弃旧的数组。在大多数情况下,你可以在创建stringbuffer的时候指定大小,这样就避免了在容量不够的时候自动增长,以提高性能。
例子:
public class rsbc { void method () { stringbuffer buffer = new stringbuffer(); // violation buffer.append ("hello"); } }
更正:
为stringbuffer提供寝大小。
public class rsbc { void method () { stringbuffer buffer = new stringbuffer(max); buffer.append ("hello"); } private final int max = 100; }
二十一、尽可能的使用栈变量
如果一个变量需要经常访问,那么你就需要考虑这个变量的作用域了。static? local?还是实例变量?访问静态变量和实例变量将会比访问局部变量多耗费2-3个时钟周期。
例子:
public class usv { void getsum (int[] values) { for (int i=0; i < value.length; i++) { _sum += value[i]; // violation. } } void getsum2 (int[] values) { for (int i=0; i < value.length; i++) { _staticsum += value[i]; } } private int _sum; private static int _staticsum; }
更正:
如果可能,请使用局部变量作为你经常访问的变量。
你可以按下面的方法来修改getsum()方法:
void getsum (int[] values) { int sum = _sum; // temporary local variable. for (int i=0; i < value.length; i++) { sum += value[i]; } _sum = sum; }
二十二、不要总是使用取反操作符(!)
取反操作符(!)降低程序的可读性,所以不要总是使用。
例子:
public class dun { boolean method (boolean a, boolean b) { if (!a) return !a; else return !b; } }
更正:
如果可能不要使用取反操作符(!)
二十三、与一个接口 进行instanceof操作
基于接口的设计通常是件好事,因为它允许有不同的实现,而又保持灵活。只要可能,对一个对象进行instanceof操作,以判断它是否某一接口要比是否某一个类要快。
例子:
public class insof { private void method (object o) { if (o instanceof interfacebase) { } // better if (o instanceof classbase) { } // worse. } } class classbase {} interface interfacebase {}
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