How to pass parameters to php under shell command-PHP Tutorial-php.cn

Usually PHP makes HTTP requests, and you can use GET or POST to receive parameters. Sometimes you need to execute PHP as a script under a shell command, such as a scheduled task. This involves the issue of how to pass parameters to php under the shell command. There are usually three ways to pass parameters.

1. Use $argv or $argc parameter to receive


        
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Execute

[root@DELL113 lee]# /usr/local/php/bin/php test.php 接收到1个参数 Array ( [0] => test.php ) [root@DELL113 lee]# /usr/local/php/bin/php test.php a b c d 接收到5个参数Array ( [0] => test.php [1] => a [2] => b [3] => c [4] => d ) [root@DELL113 lee]#

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2. Usegetopt Function


        
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Execution

[root@DELL113 lee]# /usr/local/php/bin/php test.php -a 345 Array ( [a] => 345 ) [root@DELL113 lee]# /usr/local/php/bin/php test.php -a 345 -b 12q3 Array ( [a] => 345 [b] => 12q3 ) [root@DELL113 lee]# /usr/local/php/bin/php test.php -a 345 -b 12q3 -e 3322ff Array ( [a] => 345 [b] => 12q3 )

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3. Prompt the user to input


        
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Execution

[root@DELL113 lee]# /usr/local/php/bin/php test.php

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Please enter your blog name:
The information you entered is:
You can also do this, preventing users from entering empty information


        
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Execute

[root@DELL113 lee]# /usr/local/php/bin/php test.php 请输入您的博客名： 抱歉，博客名不能为空，请重新输入您的博客名： 您输入的信息是：

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