Swap variables
x = 6 y = 5 x, y = y, x print x >>> 5 print y >>> 6
if statement inline
print "Hello" if True else "World" >>> Hello
Connection
The last way below looks cool when binding two objects of different types.
nfc = ["Packers", "49ers"] afc = ["Ravens", "Patriots"] print nfc + afc >>> ['Packers', '49ers', 'Ravens', 'Patriots'] print str(1) + " world" >>> 1 world print `1` + " world" >>> 1 world print 1, "world" >>> 1 world print nfc, 1 >>> ['Packers', '49ers'] 1
Calculation skills
#向下取整 print 5.0//2 >>> 2 # 2的5次方 print 2**5 >> 32
Pay attention to the division of floating point numbers
print .3/.1 >>> 2.9999999999999996 print .3//.1 >>> 2.0
Numerical comparison
x = 2 if 3 > x > 1: print x >>> 2 if 1 < x > 0: print x >>> 2
Iterate two lists at the same time
nfc = ["Packers", "49ers"] afc = ["Ravens", "Patriots"] for teama, teamb in zip(nfc, afc): print teama + " vs. " + teamb >>> Packers vs. Ravens >>> 49ers vs. Patriots
Indexed list iteration
teams = ["Packers", "49ers", "Ravens", "Patriots"] for index, team in enumerate(teams): print index, team >>> 0 Packers >>> 1 49ers >>> 2 Ravens >>> 3 Patriots
List derivation
Given a list, brush out the even numbers List methods:
numbers = [1,2,3,4,5,6] even = [] for number in numbers: if number%2 == 0: even.append(number)
Replace with the following
numbers = [1,2,3,4,5,6] even = [number for number in numbers if number%2 == 0]
Dictionary derivation
teams = ["Packers", "49ers", "Ravens", "Patriots"] print {key: value for value, key in enumerate(teams)} >>> {'49ers': 1, 'Ravens': 2, 'Patriots': 3, 'Packers': 0}
Initialize the value of the list
items = [0]*3 print items >>> [0,0,0]
Convert the list into a string
teams = ["Packers", "49ers", "Ravens", "Patriots"] print ", ".join(teams) >>> 'Packers, 49ers, Ravens, Patriots'
Get elements from the dictionary
Do not replace with the following
data = {'user': 1, 'name': 'Max', 'three': 4} try: is_admin = data['admin'] except KeyError: is_admin = False
Get a sublist for
data = {'user': 1, 'name': 'Max', 'three': 4} is_admin = data.get('admin', False)
x = [1,2,3,4,5,6] #前3个 print x[:3] >>> [1,2,3] #中间4个 print x[1:5] >>> [2,3,4,5] #最后3个 print x[-3:] >>> [4,5,6] #奇数项 print x[::2] >>> [1,3,5] #偶数项 print x[1::2] >>> [2,4,6]
60 characters to solve FizzBuzz
Some time ago Jeff Atwood promoted a simple programming exercise called FizzBuzz. The question is quoted as follows:
Write a program to print the numbers 1 to 100, Multiples of 3 print "Fizz" to replace the number, multiples of 5 print "Buzz", and "FizzBuzz" is printed for numbers that are both multiples of 3 and 5.
Here is a short way to solve this problem:
for x in range(101):print"fizz"[x%3*4::]+"buzz"[x%5*4::]or x
Collections
Use the Counter library
from collections import Counter print Counter("hello") >>> Counter({'l': 2, 'h': 1, 'e': 1, 'o': 1})
Iteration tools
Like the collections library, there is also a library called itertools
from itertools import combinations teams = ["Packers", "49ers", "Ravens", "Patriots"] for game in combinations(teams, 2): print game >>> ('Packers', '49ers') >>> ('Packers', 'Ravens') >>> ('Packers', 'Patriots') >>> ('49ers', 'Ravens') >>> ('49ers', 'Patriots') >>> ('Ravens', 'Patriots') False == True
In python, True and False is a global variable, so:
False = True if False: print "Hello" else: print "World" >>> Hello