if (in_array('o', $a)) {
echo "'o' was foundn";
}
?>
The above example will output:
'ph' was found
'o ' was found
Things to note:
If:
First declare an array as:
$arr = array(
*
);
Then:
in_array(0, $arr) == true
Puzzling!
{Weak language}
Solution:
in_array(strval(0), $arr, true))
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TechArticle
in_array (PHP 4, PHP 5) in_array — Check whether a certain value exists in the array. Instructions for copying the code are as follows: bool in_array ( mixed $needle , array $haystack [, bool $strict ] ) in h...