This article describes the example of how PHP determines the image type by obtaining header information. Share it with everyone for your reference. The specific implementation method is as follows:
$filename = '617.gif' ; function pictype ( $file ) { /*$png_header = "/x89/x50/x4e/x47/x0d/x0a/x1a/x0a"; $jpg_header = "/xff/xd8";*/ $header = file_get_contents ( $file , 0 , NULL , 0 , 5 ); //echo bin2hex($header); if ( $header { 0 }. $header { 1 }== "/x89/x50" ) { return 'png' ; } else if( $header { 0 }. $header { 1 } == "/xff/xd8" ) { return 'jpeg' ; } else if( $header { 0 }. $header { 1 }. $header { 2 } == "/x47/x49/x46" ) { if( $header { 4 } == "/x37" ) return 'gif87' ; else if( $header { 4 } == "/x39" ) return 'gif89' ; } } echo pictype ( $filename );
I hope this article will be helpful to everyone’s PHP programming design.