请教一个正则

WBOY
Release: 2016-06-23 14:12:09
Original
793 people have browsed it

请教一个正则:
数据有时候是这样:
["二s","李s","王s","一s"]
[{"DEVID":1,"Area":"广州","USERID":null,"USERNAME":"王s","DEVTYPE":null,"DevName":"iPad2","DevIMEI":"IPAD2346523985687","IsUsable":1,"BindDate":"2013-05-13T09:05:33","UPDATEUSER":null,"UPDATETIME":"0001-01-01T00:00:00"}]
或者
["二s","李s","王s","一s"]
或者
[{"DEVID":1,"Area":"广州","USERID":null,"USERNAME":"王s","DEVTYPE":null,"DevName":"iPad2","DevIMEI":"IPAD2346523985687","IsUsable":1,"BindDate":"2013-05-13T09:05:33","UPDATEUSER":null,"UPDATETIME":"0001-01-01T00:00:00"}]

在代码中如何判断这种字符中是否包含 ][ 呢?

success: function (returnValue) { //select var returnJson = returnValue.split('][')[0] + ']'; var returnValue1 = '[' + returnValue.split('][')[1];
Copy after login

这样有时会报错,我想用个正则来判断字符中是否存在 ][ 来截取数据


回复讨论(解决方案)

indexOf() 方法

你那不就是 json 吗?干嘛要字符串截取?

你那不就是 json 吗?干嘛要字符串截取?
["二s","李s","王s","一s"]这段要单独拿出 放在下拉框中

[{"DEVID":1,"Area":"广州","USERID":null,"USERNAME":"王s","DEVTYPE":null,"DevName":"iPad2","DevIMEI":"IPAD2346523985687","IsUsable":1,"BindDate":"2013-05-13T09:05:33","UPDATEUSER":null,"UPDATETIME":"0001-01-01T00:00:00"}]
这段要形成表格

有时候是有2段数据,有时候只有后面一段数据。所以我想判断一下是否有2段数据。该怎么写呢?

indexOf() 方法

var str="Hello world!"//值大于0,有2段数据,则截取。否则就是一段数据,直接赋值不截取。是这个意思吗?if(returnValue.indexOf("][") > 0) { var returnJson = returnValue.split('][')[0] + ']'; var returnValue1 = '[' + returnValue.split('][')[1];...}else{ var returnValue;}
Copy after login

indexOf() 方法

 //我这样测试了一下,var returnValue = "[1][2]"的时候是可以,但是var returnValue = "[1]";的时候就不行,该怎么做呢?
Copy after login

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!