jpgraph 绘图问题

WBOY
Release: 2016-06-23 13:53:44
Original
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require_once ('/usr/share/jpgraph/jpgraph.php');
require_once ('/usr/share/jpgraph/jpgraph_line.php');
require_once ('/usr/share/jpgraph/jpgraph_scatter.php');
require_once ('/usr/share/jpgraph/jpgraph_bar.php');

$datay1 = array(33,20,24,5,38,24,22);
$datay2 = array(9,7,10,25,10,8,4);

// Setup the graph
$graph = new Graph(600,450);

$graph->SetScale("textlin",0,50);
//$theme_class= new UniversalTheme;
//$graph->SetTheme($theme_class);


$graph->title->Set("Line Plots with Markers");

$graph->SetBox(false);

//$graph->ygrid->SetFill(false);
// $graph->yaxis->HideLine(false);
// $graph->yaxis->HideTicks(false,false);
//$graph->yaxis->HideZeroLabel();
[color=#FF0000][/color]

$graph->xaxis->SetTickLabels(array('A','B','C','D','E','F','G'));
// Create the plot
$p1 = new LinePlot($datay1);
$graph->Add($p1);

$p2 = new LinePlot($datay2);
$graph->Add($p2);

// Use an image of favourite car as marker
$p1->mark->SetType(MARK_IMG,'new1.gif',0.8);
$p1->SetColor('#aadddd');
$p1->value->SetFormat('%d');
$p1->value->Show();
$p1->value->SetColor('#55bbdd');

$p2->mark->SetType(MARK_IMG,'new2.gif',0.8);
$p2->SetColor('#ddaa99');
$p2->value->SetFormat('%d');
$p2->value->Show();
$p2->value->SetColor('#55bbdd');
$graph->Stroke();
?>

为什么加上红色的行就不能显示代码了?感觉是函数找不到,但具体怎么弄阿?


回复讨论(解决方案)

注释掉 $graph->Stroke(); 就应该能看到错误信息

注释掉了之后图形显示不了,也没有错误信息的啊

那就没有错呗

这个类UniversalTheme代码 可能有语法错误。

//$theme_class= new UniversalTheme;
//$graph->SetTheme($theme_class);

//$graph->ygrid->SetFill(false);
// $graph->yaxis->HideLine(false);
// $graph->yaxis->HideTicks(false,false);
//$graph->yaxis->HideZeroLabel();
如果在这几行代码下面加入输出信息 ,比如 echo"OK";
这个OK是显示不出来的,感觉是这几行函数调用有问题,执行到这里就不往下执行了。只能把这几行注释掉,先做做看了。

估计安装的时候少了什么东西,也不纠结这个问题了,还是试试用gnuplot 画图吧。

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