thinkphp

WBOY
Release: 2016-06-23 13:47:08
Original
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为什么if标签判断的不能起作用??求解,在线等

public function editestudent(){
$db=M('students');

if(IS_POST){

$stu_id=I('stu_id');
$stu_name=I('stu_name');
$cla_id=I('cla_id');
$data=array('stu_name'=>I('stu_name'),'cla_id'=>I('cla_id'));
$id=$db->data($data)->where('stu_id='.$stu_id)->save();
if($id){
$this->success('学生修改成功','liststudent');
}else{
$this->error('学生修改失败');
}

}else{
$stu_id=I('stu_id');
$arr=$db->find($stu_id);
//dump($arr);
$this->assign('array',$arr);

$n=M('classs');
$arra=$n->select();
//dump($arra);
$this->assign('edite',$arra);
$this->display();
}






nbsp;html public "-//w3c//dtd html 4.0 transitional//en">


 New Document 

<script> <br /> function checkform(f){ <br /> if(f.cla_name.value==""){ <br /> alert("学生姓名名不能为空!"); <br /> return false; <br /> }else{ <br /> return true; <br /> } <br /> <br /> } <br /> </script> 


















学生姓名
        

学生班级








回复讨论(解决方案)

看标签没问题。
可以打印出$v.cla_id eq $array.stu_id 看看是否相等。

输出比较的数组和变量的值看看。

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