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如何做数据库的行列转置

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Release: 2016-06-23 13:39:38
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thinkphp和mysql。数据库如图所示:

建表的sql语句如下:

CREATE TABLE `score_collect` (   `std_id` int(10) NOT NULL,   `course_id` int(11) NOT NULL,   `score` varchar(255) DEFAULT NULL,   PRIMARY KEY (`std_id`,`course_id`), )
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INSERT INTO `score_collect` VALUES ('2012508082', '2', '20'); INSERT INTO `score_collect` VALUES ('2012508082', '3', '10'); INSERT INTO `score_collect` VALUES ('2012508082', '4', '30'); INSERT INTO `score_collect` VALUES ('2012508084', '2', '21'); INSERT INTO `score_collect` VALUES ('2012508084', '3', '11'); INSERT INTO `score_collect` VALUES ('2012508084', '4', '31');
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需要实现的是将上图中的数据调整为这样在前台显示出来:

其中,表行数不固定。std_id和course_id也不固定。
(不知道我把问题表达清楚了没有)。用php也可以,但是我想最好还是用sql语句吧。当然。。能兼顾性能最好。
跪求各路大神解决,谢谢。
另外祝大家春节快乐,万事如意。 谢谢


回复讨论(解决方案)

SELECT std_id,GROUP_CONCAT(course_id) AS course_id,GROUP_CONCAT(score) AS score FROM `score_collect` GROUP BY std_id;
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//$list=array(array('std_id'=>'2012508082','course_id'=>'2,3,4','score'=>'20,10,30'),array('std_id'=>'2012508084','course_id'=>'2,3,4','score'=>'21,11,31'),);foreach($list as $key=>$val){	$course_id_arr=explode(',',$val['course_id']);	$score_arr=explode(',',$val['score']);	unset($list[$key]['course_id']);	unset($list[$key]['score']);	foreach($course_id_arr as $key1=>$val1)	{		$list[$key][$val1]=$score_arr[$key1];	}}print_r($list);
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